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0=-4.9t^2+98t+6
We move all terms to the left:
0-(-4.9t^2+98t+6)=0
We add all the numbers together, and all the variables
-(-4.9t^2+98t+6)=0
We get rid of parentheses
4.9t^2-98t-6=0
a = 4.9; b = -98; c = -6;
Δ = b2-4ac
Δ = -982-4·4.9·(-6)
Δ = 9721.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-\sqrt{9721.6}}{2*4.9}=\frac{98-\sqrt{9721.6}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+\sqrt{9721.6}}{2*4.9}=\frac{98+\sqrt{9721.6}}{9.8} $
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